4/3/2023 0 Comments Dnd 3.5 health calculator![]() ![]() The best methods of destroying the planet don't care about specific amounts of HP, they care about time. I suppose an ad hoc could be included to cause each particle to be propelled a distance proportional to the damage dealt. Thus, dealing 1.5 septillion damage to each thing particle by particle should separate connections between the particles. A 10d6 maximized fireball with 3 enemies in the area does 60 damage to each of those enemies (provided they fail their save). If the effect spread knocked everything outward far enough that the objects would float into the sun or out into space, then cool, but we would need that effect included.Well, I'm not sure, but I think that the power would deal damage to everything (particle by particle) within the area of effect. Even if the end result is "disintegrated" that's still a dust cloud with the same amount of matter, all sitting where the planet had been forced together by gravity. He could turn it into a giant fireball shedding heat and atmosphere, but destroying it requires some sort of dispersal effect for the material that won't turn to gas. One thing that might be calculable: how hard would it be to Telekinesis the Earth into lots of little bits, each of which was far enough apart that another Earth wouldn't just re-form swiftly? Mass calculations ought to be a lot easier than hit points.Īll he's doing is pumping energy into the planet without giving it a reason to disperse or annihilating matter. Which, I mean, destroying the entire planet crust and a significant portion of the ice caps and possibly evaporating a significant portion of ocean won't exactly leave the planet in a good state, but if the plan is to leave some dust or a pile of fragments, you'll need something clever. Not only will it be difficult to completely engulf it in an area attack, but even if you do, you'll really just be destroying the top layer of the planet rather than the entire thing. Which also makes destroying the entire planet in one go hard. Each patch of dirt and stone, each volume of water and magma will have its own stats and hit points. Something as big and diverse in composition as an entire planet would almost certainly be modeled in the same way. For example, when attacking Wall of Stone there is no single attack that will take out the entire thing- you attack it in sections, and each section has its own separate amount of hit points. When it comes to large objects and terrain, D&D rarely models them as a single entity. I just love back of the envelope calculations. Improve area to 10000 mile cubes from 10 foot cubes = +21120000 I'm definitely overestimating if damage is dealt to each part of the object, but let's go for it anyways. Next, I'm going to try to calculate an epic spell that could destroy such an object.Įnergy Seed Psionic Power (cuz psionics is cool). Probably a way overestimate (since I basically packed the entire hit points of a very big tree almost twice into a 1 foot cube of iron (wood has 10 hp/inch vs 30 hp/inch)). Maybe it would be better to just calculate it by the hit points of a 1 foot cube of iron and then extrapolate that outwards. So, a rough estimate of the earth's hit points is 17 billion. The circumference of an object = pi x diameter.ĥ70240000 * 30 = 17,107,200,000 hit points.Īt the very least, this means you would need to deal around 17 billion damage to go through the earth (if it were made of solid iron). Let's pretend the circumference of the earth is exactly 27000 miles (it's less). Let's pretend the earth is made of solid iron (hardness 10, hp 30/inch). (I'm assuming that the hit points of the earth can be calculated by looking at it's "thickness") Well, I want to apply some very "back of the envelope" calculations to get an overestimate. ![]() I googled, and saw 1 thread which gave no actual answer. ![]()
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